关于一个数组的问题

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var a_igarr = {"url":[10,20,30,40,50,60,70],"title":[100,200,300,400,500,600,700],"title2":[150,250,350,450,550,650,750]}; 怎么样用 js each，算出这个 a_igarr.url 加 a_igarr.title 以及 a_igarr.title2 总值的数组

a_igarr 这个值里面的值可能会有很多个

最后得到这个值是一个数组 var con_all = [260,460,660,860,1060,1260,1460]

a_igarr

数组

title2

var

3 replies • 2018-04-19 09:56:21 +08:00

lsvih

Apr 18, 2018

试试这个

```
var a_igarr = {"url":[10,20,30,40,50,60,70],"title":[100,200,300,400,500,600,700],"title2":[150,250,350,450,550,650,750]};

let r=[];for(let item in a_igarr){r.push(a_igarr[item])};let con_all=r.reduce((j,a)=>{a.forEach((b,k)=>j[k] = ((j[k] || 0) + b));return j},[])
```

Colorful

Apr 19, 2018

@lsvih 这个是可以，但我又仔细看了下我的问题。是我搞错了，格式应该是这样的

var a_igarr2 = [{"name":"aaa",data:[10,20,30,40,50,60,70]},{"name":"bbb","data":[100,200,300,400,500,600,700]},{"name":"ccc","data":[150,250,350,450,550,650,750]}];
然后得出一个数组的值
var con_all = [260,460,660,860,1060,1260,1460]
没想到好的思路

Colorful

Apr 19, 2018

@lsvih 解决了，谢谢你啊，按照你给的思路，已经解决了，太感谢了