有没有比较优雅的合并两个列表的方法？

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This topic created in 1831 days ago, the information mentioned may be changed or developed.

a = [1,2]
b = [a,b,c,f]

l = [[1,a],[1,b],[1,c],[1,f],[2,a],[2,b],[2,c],[2,f]]

请问，除了双层 for 循环之外还有别的办法吗？

列表

请问

双层

合并

19 replies • 2021-04-28 09:06:17 +08:00

cassidyhere

Apr 22, 2021

from itertools import product
product(a, b)

abersheeran

Apr 22, 2021 via Android

你这不叫合并，你这是算笛卡尔积。循环是少不了的，但是写法可以不一样。用 map 或者推导式。

ZoeYn

Apr 22, 2021

@cassidyhere 试了一下，可以！！

ZoeYn

Apr 22, 2021

@abersheeran 搜嘎！我去补一补这个知识，谢谢！

JackCooper

Apr 22, 2021

ruby 的话

2.5.7 :001 > a = [1,2,3,4]
=> [1, 2, 3, 4]
2.5.7 :002 > b = ['a', 'b' ,'c', 'd']
=> ["a", "b", "c", "d"]
2.5.7 :003 > a.zip(b)
=> [[1, "a"], [2, "b"], [3, "c"], [4, "d"]]

hyrious

Apr 22, 2021

@JackCooper a.product(b)

encounter2017

Apr 22, 2021

python 的话

from itertools import product
a = [1,2]
b = ['a','b','c']

list(product(a,b))
# [(1, 'a'), (1, 'b'), (1, 'c'), (2, 'a'), (2, 'b'), (2, 'c')]

scala 的话

scala> for {
| a <- List(1, 2)
| b <- List('a', 'b', 'c')
| } yield (a,b)
val res1: List[(Int, Char)] = List((1,a), (1,b), (1,c), (2,a), (2,b), (2,c))