求教，我有一组字典数据，想得到： data 里的数每三个一组，把后面的 f,z,l,t 列按竖输出。

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This topic created in 1831 days ago, the information mentioned may be changed or developed.

datas={'name': 'xxxx ', 'leixing': '2', 'data': 'BBPPPPBPPPBPBBBBPBPB', 'f': '**√√', 'z': '√√*√√√', 'l': '√√√x√x', 't': '√x√√x√'}

效果如下： https://z3.ax1x.com/2021/04/26/gS1jr6.jpg

6 replies • 2021-04-27 00:37:19 +08:00

imn1

Apr 26, 2021

图片和例子不同，逻辑对应不了

princelai

Apr 26, 2021

描述的不清楚没能理解

no1xsyzy

Apr 26, 2021

（等你描述清楚了，你也就写出来了。

chionetw5

Apr 26, 2021

datas={'name': 'xxxx ', 'leixing': '2', 'data': 'BBPPPPBPPPBPBBBBPBPB', 'f': '**√√', 'z': '√√*√√√', 'l': '√√√x√x', 't': '√x√√x√'}
group_data = [datas['data'][_:_+3] for _ in range(0,len(datas['data']), 3)]
for index, data in enumerate(group_data):
print(datas['name'], datas['leixing'], data, datas['f'][index:index+1], datas['z'][index:index+1], datas['l'][index:index+1], datas['t'][index:index+1])

hellogitooxx

Apr 26, 2021

@chionetw5 感谢你，就是这个意思

zzxgz

Apr 27, 2021

leixing 还行