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This topic created in 1603 days ago, the information mentioned may be changed or developed.
如题，有一个 json 文件，
[
{
"id": 0001,
"name": "Zhang.San_123456",
"email": {
"qqmail": "[email protected]",
"163mail": "[email protected]"
},
"Address": {
"Province": "Guangdong",
"City": "Zhanjiang",
"Country": "Xuwen"
}
},
{
"id": 0002,
"name": "Li.Si_123456",
"email": {
"qqmail": "[email protected]",
"163mail": "[email protected]"
},
"Address": {
"Province": "Sichuan",
"City": "Yibin",
"Country": "Jiang'an"
}
},
{
"id": 0003,
"name": "Wang.Wu_123456",
"email": {
"qqmail": "[email protected]",
"163mail": "[email protected]"
},
"Address": {
"Province": "Shanxi",
"City": "Taiyuan",
"Country": "Qingxu"
}
}
]
我想获取里面 name 字段为 Li.Si_123456 的一部分，返回时移除 email 里的 163mail ，返回内容如下：
[
{
"id": 0002,
"name": "Li.Si_123456",
"url": "http://xxx.com",
"qqmail": "[email protected]",
"Address": {
"Province": "Sichuan",
"City": "Yibin",
"Country": "Jiang'an"
}
}
]
请教一下这个使用 jq 处理应该怎么写呢，有大佬能指教一下吗？谢谢了^^
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1
0ZXYDDu796nVCFxq Dec 12, 2021 via Android
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3
Ryanjie OP 解决方法：
1. 获取里面 name 字段为 Li.Si_123456 的一部分：`jq --arg NAME ${UserName} '.[] | select(.name==$NAME)'` 2. 返回时移除 email 里的 163mail: `map({id, name, url, qqmail: .email.qqmail,...})` |
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