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Oct 7, 2018 Replied to a topic by theworldsong › 程序员 › Java : 方法接受一个 Map 参数，需要对这个 map 做遍历。怎样才是安全的？ |
# 如果只是解决报错的问题的话
String[] keys = map.keySet().toArray(new String[map.size()]);
for (String key : keys) {
String value = map.get(key);
if (value == null) {
// do something
}
//do others something
}
# 如果不只是解决报错的话，那设计的接口有问题
String[] keys = map.keySet().toArray(new String[map.size()]);
for (String key : keys) {
String value = map.get(key);
if (value == null) {
// do something
}
//do others something
}
# 如果不只是解决报错的话，那设计的接口有问题
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